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WGU Foundations of Programming (Python) - E010 JIV1 : Foundations-of-Programming-Python Exam Questions
- Exam Code: Foundations-of-Programming-Python
- Exam Name: Foundations of Programming (Python) - E010 JIV1
- Updated: Oct 09, 2026
- Q&As: 62 Questions and Answers
About WGU Foundations of Programming (Python) - E010 JIV1 Exam Braindumps
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WGU Foundations-of-Programming-Python Exam Syllabus Topics:
| Section | Objectives |
|---|---|
| Functions | - Return Values - Scope (local and global) - Function Definition and Call - Recursion - Parameters and Arguments |
| Testing and Debugging | - Unit Testing Concepts - Debugging Techniques - Trace Errors |
| Python Fundamentals | - Variables and Data Types - Type Conversion - Operators and Expressions - Input/Output Operations |
| Object-Oriented Programming | - Encapsulation - Constructors (__init__) - Classes and Objects - Inheritance - Attributes and Methods |
| Control Structures | - Nested Conditionals and Loops - Loops (for, while) - Conditional Statements (if, elif, else) - Loop Control (break, continue, pass) |
| File Handling and Exceptions | - Custom Exceptions - Exception Handling (try, except, finally) - Reading and Writing Files |
| Data Structures | - Dictionaries - Lists and List Operations - String Manipulation - Sets - Tuples |
WGU Foundations of Programming (Python) - E010 JIV1 Sample Questions:
Question #1
A program uses this while loop to count down:
count = 5
while count > 0:
print(count)
Which issue is preventing the loop from working correctly?
- A. The condition should use > = instead of > .
- B. The variable should be named differently.
- C. It runs infinitely because count is never modified.
- D. There is a missing colon after the condition.
Correct Answer: C 🗳️
Explanation: Only visible for VCEPrep members. You can sign-up / login (it's free).
Question #2
Complete the function add_item(numeric_list, new_number) that takes a list of numbers and a new number, and returns a new list that appends the new number to the end of the list.
For example, add_item([1, 2, 3], 4) should return [1, 2, 3, 4] .
- A. def add_item(numeric_list, new_number):return new_number
- B. def add_item(numeric_list, new_number):numeric_list.append(new_number)return numeric_list
- C. def add_item(numeric_list, new_number):numeric_list.remove(new_number)return numeric_list
- D. def add_item(numeric_list, new_number):pass
Correct Answer: B 🗳️
Explanation: Only visible for VCEPrep members. You can sign-up / login (it's free).
Question #3
What does the string method ' ' .join() return when applied to the list [ ' Hello ' , ' World ' ]?
- A. ' Hello World '
- B. ' Hello,World '
- C. ' HelloWorld '
- D. ' Hello, World '
Correct Answer: C 🗳️
Explanation: Only visible for VCEPrep members. You can sign-up / login (it's free).
Question #4
Fix the missing return statement in this function that should return whether a number is even.
def is_even(number):
if number % 2 == 0:
True
else:
False
Correct Answer:
See the Step by Step Solution below in Explanation.
Explanation:
Step 1: The expression number % 2 == 0 checks whether the number is even.
Step 2: The original code writes True and False, but it does not return them.
Step 3: A function must use the return statement to send a value back to the caller.
Correct code:
def is_even(number):
if number % 2 == 0:
return True
else:
return False
Simplified correct code:
def is_even(number):
return number % 2 == 0
Example:
print(is_even(4))
print(is_even(7))
Output:
True
False
Question #5
Write a complete function reverse_string(text) that takes a string and returns it reversed.
For example, reverse_string( " hello " ) should return " olleh " .
def reverse_string(text):
# TODO: Return the reversed string
pass
Correct Answer:
See the Step by Step Solution below in Explanation.
Explanation:
Step 1: The function receives one string parameter named text.
Step 2: Python slicing can be used to reverse a string.
Step 3: The slice [::-1] means start at the end of the string and move backward by one character at a time.
Step 4: Return text[::-1].
Correct code:
def reverse_string(text):
return text[::-1]
Example:
print(reverse_string( " hello " ))
Output:
olleh
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